Standard loci in the complex plane
A locus is the set of all points that follow a rule. Translate modulus as distance and argument as direction before doing coordinate algebra.
Recognise the three standard objects
The difference is the displacement from the fixed point a to the moving point z. Therefore is their distance and is the direction from a to z.
Translate the locus before sketching
|z − a| = r
fixed distance → circle
|z − a| = |z − b|
equal distances → perpendicular bisector
arg(z − a) = θ
fixed direction → ray
- : circle with centre a and radius r.
- : perpendicular bisector of the segment joining a and b.
- : ray from a at direction α.
Equality draws a boundary; inequality chooses a side
- is the inside of the circle without the circumference.
- includes the circumference.
- is the half-plane closer to a than b.
- is on or left of ; is on or above .
- An argument inequality creates a wedge. Test a simple point if the direction of shading is uncertain.
Worked example
Convert an equal-distance locus to a line
Let and . Write .
This line passes through the midpoint and is perpendicular to the segment ab.
Combined conditions mean intersection
Draw each condition separately, then keep only the points satisfying all conditions. Mark included boundaries solid and excluded boundaries dashed or open.
A ray starts at a and points in the direction α. The point a itself is excluded because there , whose argument is undefined.
Describe the region satisfying and . State any excluded point.
Show worked answer
Keep the quarter-disc of radius 2 lying to the right of and above . The circular arc and both radial boundaries are included.
Excluded point: , because its argument is undefined.
Examiner note
(Pure Mathematics 2 & 3 Coursebook, Ch. 11.5)
