Internal Energy
Internal Energy
- Heat a stone and it gets no higher and no faster — yet the energy went somewhere. This lesson names that somewhere, in the exact words the mark scheme pays for.
The definition (two marks)
- The of a system is the sum of the kinetic and potential energies of its molecules, associated with their random motion. The sum is one mark; the word random is the other (9702/42/O/N/23 Q3(a)) (9702/42/M/J/24 Q3(a)) (9702/41/M/J/25 Q4(a)(i)).
- Why random matters: throw the stone and every molecule gains ordered kinetic energy together — that is the stone's kinetic energy, not its internal energy. Internal energy only counts the disordered part: molecules vibrating and darting in all directions, plus the potential energy stored in their separations.
- Two dials therefore change a system's internal energy from inside: temperature (the kinetic part — recall from the Ideal Gases chapter) and molecular separation (the potential part — the idea behind latent heat in the Temperature chapter).
- Special case worth two marks on its own: an ideal gas has no intermolecular forces, so its molecular potential energy is zero and is purely kinetic — which is why (9702/41/M/J/24 Q3(a)(ii)) (9702/42/F/M/24 Q2(a)).
The KE/PE two-step
- A whole family of 3-markers asks what happens to internal energy in some process, “with reference to the kinetic and potential energies of the molecules”. The recipe: deal with KE via temperature, then PE via separation, then conclude about .
| Process | KE (temperature) | PE (separation) | So U... |
|---|---|---|---|
| gas heated at constant volume | rises — T rises | unchanged — same separation | increases |
| wire stretched at constant temperature | unchanged — T constant | rises — separation increases | increases |
| water boiling at 100 °C | unchanged — T constant | rises — molecules pulled apart | increases |
- Each row is a real mark scheme: the heated gas and the stretched wire were one question's two halves (9702/42/M/J/24 Q3(b)), and the boiling-water row is the standard explanation of why temperature stays constant during vaporisation (9702/41/O/N/25 Q2(b)(ii)).
Internal energy = sum of random KE + PE of the molecules. Analyse any process in two steps: KE follows temperature, PE follows separation.